ប្រមាណវិធីលើរ៉ាឌីកាល់
ប្រធានលំហាត់
ចូលគណនា និងសម្រួលកន្សោមរ៉ាឌីកាល់ខាងក្រោម៖
- 1. $A = \sqrt{12} + \sqrt{27}$
- 2. $B = 3\sqrt{50} - 2\sqrt{18}$
- 3. $C = \sqrt{8} + \sqrt{18} - \sqrt{32}$
- 4. $D = 2\sqrt{20} - \sqrt{45} + 3\sqrt{5}$
- 5. $E = \sqrt{3} \times \sqrt{12}$
- 6. $F = 2\sqrt{5} \times 3\sqrt{15}$
- 7. $G = \sqrt{2}(\sqrt{8} - \sqrt{18})$
- 8. $H = (\sqrt{7} - \sqrt{5})(\sqrt{7} + \sqrt{5})$
- 9. $I = \frac{\sqrt{50}}{\sqrt{2}}$
- 10. $J = \frac{8\sqrt{45}}{2\sqrt{5}}$
- 11. $K = \frac{\sqrt{24} \times \sqrt{3}}{\sqrt{2}}$
- 12. $L = (\sqrt{3} + 1)^{2}$
- 13. $M = \sqrt{75} + 2\sqrt{48} - \sqrt{108}$
ចម្លើយ និងដំណោះស្រាយសង្ខេប
- 1. $A = \sqrt{4 \times 3} + \sqrt{9 \times 3} = 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}$
- 2. $B = 3\sqrt{25 \times 2} - 2\sqrt{9 \times 2} = 3(5\sqrt{2}) - 2(3\sqrt{2}) = 15\sqrt{2} - 6\sqrt{2} = 9\sqrt{2}$
- 3. $C = 2\sqrt{2} + 3\sqrt{2} - 4\sqrt{2} = \sqrt{2}$
- 4. $D = 2(2\sqrt{5}) - 3\sqrt{5} + 3\sqrt{5} = 4\sqrt{5} - 3\sqrt{5} + 3\sqrt{5} = 4\sqrt{5}$
- 5. $E = \sqrt{3 \times 12} = \sqrt{36} = 6$
- 6. $F = (2 \times 3)\sqrt{5 \times 15} = 6\sqrt{75} = 6(5\sqrt{3}) = 30\sqrt{3}$
- 7. $G = \sqrt{2 \times 8} - \sqrt{2 \times 18} = \sqrt{16} - \sqrt{36} = 4 - 6 = -2$
- 8. $H = (\sqrt{7})^{2} - (\sqrt{5})^{2} = 7 - 5 = 2$
- 9. $I = \sqrt{\frac{50}{2}} = \sqrt{25} = 5$
- 10. $J = (\frac{8}{2})\sqrt{\frac{45}{5}} = 4\sqrt{9} = 4 \times 3 = 12$
- 11. $K = \sqrt{\frac{24 \times 3}{2}} = \sqrt{\frac{72}{2}} = \sqrt{36} = 6$
- 12. $L = (\sqrt{3})^{2} + 2(\sqrt{3})(1) + 1^{2} = 3 + 2\sqrt{3} + 1 = 4 + 2\sqrt{3}$
- 13. $M = \sqrt{25 \times 3} + 2\sqrt{16 \times 3} - \sqrt{36 \times 3}$
$\phantom{M} = 5\sqrt{3} + 2(4\sqrt{3}) - 6\sqrt{3}$
$\phantom{M} = 5\sqrt{3} + 8\sqrt{3} - 6\sqrt{3} = 7\sqrt{3}$

.png)
0 Comments